MS ACCESS -- SQL

SELECT school_name, count(student_school_id) AS n_of_student
FROM tbl_student
GROUP BY school_name;

SELECT school_name, count(student_school_id) AS n_of_student, avg(selected_response_score) as mean_score, STDEV(selected_response_score) as SD
FROM tbl_student
GROUP BY school_name;

 

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